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7x^2-54x+99=0
a = 7; b = -54; c = +99;
Δ = b2-4ac
Δ = -542-4·7·99
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-12}{2*7}=\frac{42}{14} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+12}{2*7}=\frac{66}{14} =4+5/7 $
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